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Exercise 773Calculus › Single-variable calculus › Series › Power seriesL2Added 2 Nov 2026

Radius of convergence, four examples

#radius of convergence#ratio test#endpoints

Statement

Find the radius of convergence of each power series, and study the endpoints for the last two.

  1. ∑n! xn\displaystyle\sum n!\,x^n
  2. ∑xnn!\displaystyle\sum\frac{x^n}{n!}
  3. ∑xnn\displaystyle\sum\frac{x^n}n
  4. ∑xnn2\displaystyle\sum\frac{x^n}{n^2}
Hint

Apply d'Alembert's test to ∣anxn∣|a_nx^n|: convergence if ∣x∣<R|x|<R where R=lim⁡∣anan+1∣R=\lim\left|\frac{a_n}{a_{n+1}}\right|.

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Solution

1. ∣an+1an∣=n+1→∞\left|\frac{a_{n+1}}{a_n}\right|=n+1\to\infty, so R=0R=0: converges only at x=0x=0.

2. ∣an+1an∣=1n+1→0\left|\frac{a_{n+1}}{a_n}\right|=\frac1{n+1}\to0, so R=+∞R=+\infty: converges for all xx.

3. ∣an+1an∣=nn+1→1\left|\frac{a_{n+1}}{a_n}\right|=\frac n{n+1}\to1, so R=1R=1. At x=1x=1: harmonic series, diverges. At x=−1x=-1: alternating harmonic, converges. Interval of convergence: [−1,1)[-1,1).

4. Also R=1R=1. At x=±1x=\pm1: ∑1n2\sum\frac1{n^2} and ∑(−1)nn2\sum\frac{(-1)^n}{n^2} both converge. Interval of convergence: [−1,1][-1,1].

Remark. The endpoints are the delicate part: inside the open interval the convergence is absolute, outside the series diverges, but on the boundary anything can happen.