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Exercise 1863Logic, sets and proofs › Quantifiers and negationL1Added 3 Nov 2026

Prenex normal form

#prenex form#quantifiers#normal form

Statement

Put ¬(∀x, ∃y, P(x,y))\neg(\forall x,\ \exists y,\ P(x,y)) into prenex normal form.

Hint

Apply the negation rules.

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Solution

Negation. ¬(∀x, ∃y, P(x,y))≡∃x, ¬(∃y, P(x,y))≡∃x, ∀y, ¬P(x,y)\neg(\forall x,\ \exists y,\ P(x,y))\equiv\exists x,\ \neg(\exists y,\ P(x,y))\equiv\exists x,\ \forall y,\ \neg P(x,y).

Conclusion. The prenex form is ∃x, ∀y, ¬P(x,y)\exists x,\ \forall y,\ \neg P(x,y).

General. Every first-order formula is equivalent to one in prenex form (all quantifiers at the front).