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Exercise 1848Linear algebra › Quadratic formsL1Added 3 Nov 2026

Diagonalization by congruence

#congruence#diagonalization#quadratic form

Statement

Diagonalize the quadratic form Q(x,y)=x2+4xy+3y2Q(x,y)=x^2+4xy+3y^2 by congruence (find an invertible PP such that PTAPP^TAP is diagonal).

Hint

Use the substitution x=u−2vx=u-2v, y=vy=v that comes from completing the square.

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Solution

Reduction. Q=(x+2y)2−y2Q=(x+2y)^2-y^2. Set u=x+2yu=x+2y, v=yv=y. Then Q=u2−v2Q=u^2-v^2.

Transition matrix. From u=x+2yu=x+2y, v=yv=y: x=u−2vx=u-2v, y=vy=v. So
P=(1−201).P=\begin{pmatrix}1&-2\\0&1\end{pmatrix}.

Congruence. A=(1223)A=\begin{pmatrix}1&2\\2&3\end{pmatrix}, and
PTAP=(10−21)(1223)(1−201)=(100−1).P^TAP=\begin{pmatrix}1&0\\-2&1\end{pmatrix}\begin{pmatrix}1&2\\2&3\end{pmatrix}\begin{pmatrix}1&-2\\0&1\end{pmatrix}=\begin{pmatrix}1&0\\0&-1\end{pmatrix}.

Conclusion. Q=u2−v2Q=u^2-v^2, signature (1,1,0)(1,1,0).