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Exercise 1133Number theory › PrimesL1Added 3 Nov 2026

Euclid's lemma

#Euclid lemma#prime#divisibility

Statement

Let pp be prime. Show that if p∣abp\mid ab, then p∣ap\mid a or p∣bp\mid b.

Hint

If p∤ap\nmid a, then gcd⁡(p,a)=1\gcd(p,a)=1. Apply Gauss's lemma.

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Solution

Case 1. If p∣ap\mid a, done.

Case 2. If p∤ap\nmid a, then since pp prime, gcd⁡(p,a)=1\gcd(p,a)=1. By Gauss's lemma, p∣bp\mid b.

Conclusion. Euclid's lemma holds.

Application. Iterated: if p∣a1⋯akp\mid a_1\cdots a_k, then pp divides some aia_i.