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Exercise 540Algebra › PolynomialsHigh schoolAdded 3 Nov 2026

Vieta's formulas for a quadratic

#Vieta#sum and product of roots#quadratic

Statement

Let x1,x2x_1,x_2 be the roots of 2X2−5X+1=02X^2-5X+1=0. Compute x1+x2x_1+x_2, x1x2x_1x_2, x12+x22x_1^2+x_2^2, and 1/x1+1/x21/x_1+1/x_2.

Hint

Vieta: x1+x2=−b/a=5/2x_1+x_2=-b/a=5/2, x1x2=c/a=1/2x_1x_2=c/a=1/2.

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Solution

Vieta. x1+x2=5/2x_1+x_2=5/2, x1x2=1/2x_1x_2=1/2.

x12+x22x_1^2+x_2^2. (x1+x2)2−2x1x2=25/4−1=21/4(x_1+x_2)^2-2x_1x_2=25/4-1=21/4.

1/x1+1/x21/x_1+1/x_2. (x1+x2)/(x1x2)=(5/2)/(1/2)=5(x_1+x_2)/(x_1x_2)=(5/2)/(1/2)=5.

Conclusion. Sum 5/25/2, product 1/21/2, sum of squares 21/421/4, sum of reciprocals 55.