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Exercise 1113Algebra › PolynomialsL1Added 3 Nov 2026

Multiplicity of a root

#multiplicity#repeated root#derivative

Statement

Determine the multiplicity of X=1X=1 as a root of P(X)=X4−4X3+6X2−4X+1P(X)=X^4-4X^3+6X^2-4X+1.

Hint

A root has multiplicity kk iff P(j)(α)=0P^{(j)}(\alpha)=0 for j<kj<k and P(k)(α)≠0P^{(k)}(\alpha)\neq0.

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Solution

Compute derivatives.
P(X)=(X−1)4P(X)=(X-1)^4 (by recognizing the binomial expansion, or computing). Let us verify by successive derivatives:
- P(1)=1−4+6−4+1=0P(1)=1-4+6-4+1=0.
- P′(X)=4X3−12X2+12X−4P'(X)=4X^3-12X^2+12X-4, P′(1)=4−12+12−4=0P'(1)=4-12+12-4=0.
- P′′(X)=12X2−24X+12P''(X)=12X^2-24X+12, P′′(1)=12−24+12=0P''(1)=12-24+12=0.
- P′′′(X)=24X−24P'''(X)=24X-24, P′′′(1)=0P'''(1)=0.
- P(4)(X)=24P^{(4)}(X)=24, P(4)(1)=24≠0P^{(4)}(1)=24\neq0.

Conclusion. The multiplicity of 11 is 44, so P(X)=(X−1)4P(X)=(X-1)^4.