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Exercise 1820Algebra › PolynomialsL1Added 3 Nov 2026

Decomposition into irreducible factors

#factorization#irreducible factors#real polynomials

Statement

Factor P(X)=X4+4P(X)=X^4+4 over R\mathbb{R}.

Hint

Use Sophie Germain's identity: a4+4b4=(a2+2ab+2b2)(a2−2ab+2b2)a^4+4b^4=(a^2+2ab+2b^2)(a^2-2ab+2b^2).

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Solution

Sophie Germain. With a=Xa=X, b=1b=1:
X4+4=(X2+2X+2)(X2−2X+2).X^4+4=(X^2+2X+2)(X^2-2X+2).

Irreducibility. Each quadratic has negative discriminant: Δ=4−8=−4<0\Delta=4-8=-4<0 and Δ=4−8=−4<0\Delta=4-8=-4<0. So both are irreducible over R\mathbb{R}.

Conclusion. P(X)=(X2+2X+2)(X2−2X+2)P(X)=(X^2+2X+2)(X^2-2X+2), both factors irreducible over R\mathbb{R}.