Components of the invertible symmetric matrices
Statement
Show that the set of invertible symmetric matrices in has exactly path components, indexed by the number of positive eigenvalues.
Hint
Show that is locally constant, and that each class is the image of a connected set under .
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Solution
Idea. The signature is a continuous integer-valued invariant (the eigenvalues cannot cross without making the matrix singular), and matrices with the same signature are connected through the spectral theorem.
Step 1: continuity of eigenvalues. Let be the set of invertible symmetric matrices and the ordered eigenvalues of . By *Weyl's inequality*,
so each is continuous (even -Lipschitz) on .
Step 2: the classes are clopen. On no vanishes. The number of positive eigenvalues is . Since each is continuous and never on , the sign of each is locally constant, hence so is . So the classes , , are open, disjoint, non-empty (they contain ) and cover ; each is also closed in as a complement of the union of the others.
Step 3: each class is connected. By the spectral theorem every is with and .
- *We may take .* Let . Since , and one of has determinant .
- *Connected parameter space.* is path connected (Problem 16) and is convex. So is path connected, and is its continuous image under .
Conclusion. The path components are exactly : of them.
Remark. is the cone of positive definite matrices and its negative. for are the sets of *quadratic forms of signature *, in the classification of quadratic forms by Sylvester's law of inertia. For there are three components: the two cones , and the "inside of the light cone" .