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Exercise 125Calculus › Single-variable calculus › Differentiation › Optimisation and curve sketchingL1Added 4 Nov 2026

Maximising profit

#optimisation#economics#marginal cost#modelling

Statement

A company sells qq units at price p(q)=80−0.5qp(q)=80-0.5q (€ per unit). Producing qq units costs C(q)=200+20q+0.25q2C(q)=200+20q+0.25q^2.

  1. Write the profit Π(q)\Pi(q) and find the production level that maximises it.
  2. Check that, at the optimum, the marginal revenue equals the marginal cost.
Hint

Revenue is R(q)=q p(q)R(q)=q\,p(q). Marginal revenue and marginal cost are R′(q)R'(q) and C′(q)C'(q).

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Solution

1. The price is nonnegative for 0≤q≤1600\le q\le160. R(q)=80q−0.5q2R(q)=80q-0.5q^2, so
Π(q)=R(q)−C(q)=60q−0.75q2−200.\Pi(q)=R(q)-C(q)=60q-0.75q^2-200.
Π′(q)=60−1.5q=0\Pi'(q)=60-1.5q=0 gives q=40q=40, which lies in [0,160][0,160]; the parabola is concave, so this is the global maximum. Then p=80−20=60p=80-20=60 € and Π(40)=2400−1200−200=1000\Pi(40)=2400-1200-200=1000 €.

2. R′(q)=80−q=40R'(q)=80-q=40 and C′(q)=20+0.5q=40C'(q)=20+0.5q=40 at q=40q=40. They are equal.

Remark. Π′=0\Pi'=0 is exactly R′=C′R'=C': it is worth producing one more unit as long as the extra revenue exceeds the extra cost. This "marginal" reasoning is the heart of microeconomics.