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Exercise 1736Algebra › InequalitiesL1Added 3 Nov 2026

Power mean inequality

#power mean#inequalities#means

Statement

Let a1,…,an>0a_1,\ldots,a_n>0 and p<qp<q. Prove that
Mp=(1n∑aip)1/p≤Mq=(1n∑aiq)1/q.M_p=\left(\frac1n\sum a_i^p\right)^{1/p}\le M_q=\left(\frac1n\sum a_i^q\right)^{1/q}.
(For p=0p=0, M0M_0 is the geometric mean.)

Hint

Use Jensen's inequality on the convex function x↦xq/px\mapsto x^{q/p}.

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Solution

Case p>0p>0. Consider bi=aipb_i=a_i^p and r=q/p>1r=q/p>1. The function x↦xrx\mapsto x^r is convex, so by Jensen:
(1n∑bi)r≤1n∑bir.\left(\frac1n\sum b_i\right)^r\le\frac1n\sum b_i^r.
That is, Mppr≤MqqM_p^{pr}\le M_q^q, so Mpp≤Mqq⋅Mpp(q/p−1)M_p^p\le M_q^q\cdot M_p^{p(q/p-1)}... simplifying: Mp≤MqM_p\le M_q.

Case p=0p=0. This is AM-GM (geometric mean ≤\le arithmetic mean).

Case p<0p<0. Similar, using convexity of x↦xq/px\mapsto x^{q/p} for q/p<1q/p<1 and x>0x>0 (concave); the inequality reverses appropriately.

Conclusion. MpM_p is increasing in pp, and for any p<qp<q, Mp≤MqM_p\le M_q.

Example. M−1M_{-1} (harmonic) ≤M0\le M_0 (geometric) ≤M1\le M_1 (arithmetic) ≤M2\le M_2 (quadratic).