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Exercise 999Combinatorics › Inclusion-exclusionL1Added 3 Nov 2026

Letters and envelopes

#IE#derangements#letters

Statement

Five letters are put randomly into five envelopes. What is the probability that no letter is in its correct envelope?

Hint

Derangements: D5/5!D_5/5!.

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Solution

Compute. D5=44D_5=44, total 5!=1205!=120.

Probability. 44/120=11/30≈0.366744/120=11/30\approx0.3667.

Conclusion. Probability =11/30=11/30.

Approximation. Dn/n!→1/e≈0.368D_n/n!\to1/e\approx0.368; 11/30≈0.36711/30\approx0.367, close.