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Exercise 483Combinatorics › Inclusion-exclusionHigh schoolAdded 3 Nov 2026

Even vs odd subsets

#even subsets#odd subsets#IE

Statement

Show that the number of subsets of an nn-element set with even size equals the number with odd size, for n≥1n\ge1.

Hint

Toggle one element (bijection), or use (1−1)n=0(1-1)^n=0.

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Solution

Bijection. Map S↦S△{1}S\mapsto S\triangle\{1\}. This is an involution changing parity.

Conclusion. Even and odd subsets are equinumerous, each count 2n−12^{n-1}.