Counting numbers with at least one property

Sets.
- $|A_2|=50$, $|A_3|=33$, $|A_5|=20$.
- $|A_2\cap A_3|=16$, $|A_2\cap A_5|=10$, $|A_3\cap A_5|=6$.
- $|A_2\cap A_3\cap A_5|=3$.

IE. $50+33+20-16-10-6+3=74$.

Conclusion. $74$ integers divisible by $2$, $3$, or $5$.