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Exercise 1710Algebra › GroupsM1Added 3 Nov 2026

Simple groups

#simple group#normal subgroup#examples

Statement

Define a simple group. Show that Z/pZ\mathbb{Z}/p\mathbb{Z} is simple for pp prime, and that Z/nZ\mathbb{Z}/n\mathbb{Z} is not simple for nn composite.

Hint

A simple group has no proper non-trivial normal subgroups. In an abelian group, every subgroup is normal.

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Solution

Definition. A group is simple if its only normal subgroups are {e}\{e\} and GG.

Z/pZ\mathbb{Z}/p\mathbb{Z}. Its only subgroups are {0}\{0\} and the whole group (since pp is prime). So it has no proper non-trivial normal subgroups. Simple.

Z/nZ\mathbb{Z}/n\mathbb{Z} for composite nn. If dd divides nn with 1<d<n1<d<n, the subgroup generated by n/d‾\overline{n/d} has order dd. Since the group is abelian, this subgroup is normal. So the group is not simple.

Conclusion. Z/pZ\mathbb{Z}/p\mathbb{Z} is simple for pp prime; Z/nZ\mathbb{Z}/n\mathbb{Z} is not simple for nn composite.