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Exercise 974Algebra › GroupsL1Added 3 Nov 2026

Homomorphisms between familiar groups

#homomorphism#examples#kernels

Statement

For each map, determine whether it is a group homomorphism, and if so, compute its kernel and image:

(a) f:(Z,+)→(Z/nZ,+)f:(\mathbb{Z},+)\to(\mathbb{Z}/n\mathbb{Z},+), k↦kˉk\mapsto\bar k;
(b) g:(R,+)→(R∗,×)g:(\mathbb{R},+)\to(\mathbb{R}^*,\times), x↦exx\mapsto e^x;
(c) h:(C∗,×)→(R+∗,×)h:(\mathbb{C}^*,\times)\to(\mathbb{R}^*_+,\times), z↦∣z∣z\mapsto|z|;
(d) φ:(R,+)→(R,+)\varphi:(\mathbb{R},+)\to(\mathbb{R},+), x↦x2x\mapsto x^2.

Hint

Check f(ab)=f(a)f(b)f(ab)=f(a)f(b) (or the additive analogue).

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Solution

(a) f(k+ℓ)=k+ℓ‾=kˉ+ℓˉ=f(k)+f(ℓ)f(k+\ell)=\overline{k+\ell}=\bar k+\bar\ell=f(k)+f(\ell). Homomorphism. Kernel nZn\mathbb{Z}, image Z/nZ\mathbb{Z}/n\mathbb{Z} (surjective).

(b) g(x+y)=ex+y=exey=g(x)g(y)g(x+y)=e^{x+y}=e^xe^y=g(x)g(y). Homomorphism. Kernel {0}\{0\} (injective), image R+∗\mathbb{R}^*_+.

(c) h(zw)=∣zw∣=∣z∣∣w∣=h(z)h(w)h(zw)=|zw|=|z||w|=h(z)h(w). Homomorphism. Kernel {z:∣z∣=1}\{z:|z|=1\} (unit circle), image R+∗\mathbb{R}^*_+ (surjective).

(d) φ(x+y)=(x+y)2≠x2+y2\varphi(x+y)=(x+y)^2\neq x^2+y^2 in general. Not a homomorphism (unless the group operation is trivial).

Conclusion. (a), (b), (c) are homomorphisms; (d) is not.