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Exercise 937Linear algebra › Eigenvalues and diagonalisationL1Added 3 Nov 2026

Eigenvalues of a rotation

#rotation#complex eigenvalues#2x2 matrices

Statement

Let Rθ=(cos⁡θ−sin⁡θsin⁡θcos⁡θ)R_\theta=\begin{pmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{pmatrix} be a rotation. Compute its eigenvalues (real or complex) as a function of θ\theta.

Hint

det⁡(Rθ−λI)=λ2−2cos⁡θ⋅λ+1\det(R_\theta-\lambda I)=\lambda^2-2\cos\theta\cdot\lambda+1.

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Solution

Characteristic polynomial.
det⁡(Rθ−λI)=λ2−2cos⁡θ⋅λ+1.\det(R_\theta-\lambda I)=\lambda^2-2\cos\theta\cdot\lambda+1.
Discriminant: Δ=4cos⁡2θ−4=−4sin⁡2θ\Delta=4\cos^2\theta-4=-4\sin^2\theta.

Case sin⁡θ=0\sin\theta=0 (θ=0 or Ï€).
- θ=0\theta=0: R=IR=I, λ=1\lambda=1 (double).
- θ=π\theta=\pi: R=−IR=-I, λ=−1\lambda=-1 (double).

Case sin⁡θ≠0\sin\theta\neq0. Complex eigenvalues:
λ±=e±iθ=cos⁡θ±isin⁡θ.\lambda_{\pm}=e^{\pm i\theta}=\cos\theta\pm i\sin\theta.

Conclusion. A rotation of angle θ∉{0,π}\theta\notin\{0,\pi\} has no real eigenvalues but complex eigenvalues e±iθe^{\pm i\theta}. This reflects the fact that a non-trivial rotation has no invariant line.