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Exercise 934Linear algebra › Eigenvalues and diagonalisationL1Added 3 Nov 2026

A 3×3 matrix with distinct eigenvalues

#eigenvalues#eigenvectors#3x3 matrices

Statement

Find the eigenvalues of
A=(100020003),B=(110021003).A = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 3 \end{pmatrix}, \qquad B = \begin{pmatrix} 1 & 1 & 0 \\ 0 & 2 & 1 \\ 0 & 0 & 3 \end{pmatrix}.

Hint

Both matrices are triangular.

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Solution

Matrix AA. AA is diagonal, so its eigenvalues are its diagonal entries: 1,2,31,2,3.

Matrix BB. BB is upper triangular with diagonal entries 1,2,31,2,3, so its eigenvalues are also 1,2,31,2,3.

Remark. The eigenvalues of a triangular matrix are its diagonal entries. The two matrices AA and BB have the same eigenvalues but are not similar (the first is diagonalizable, the second is not, as we will see).