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Exercise 1619Combinatorics › Counting principlesL1Added 3 Nov 2026

Three-set counts

#inclusion-exclusion#three sets#union

Statement

Given ∣A∣=20|A|=20, ∣B∣=25|B|=25, ∣C∣=15|C|=15, ∣A∩B∣=10|A\cap B|=10, ∣A∩C∣=8|A\cap C|=8, ∣B∩C∣=5|B\cap C|=5, ∣A∩B∩C∣=3|A\cap B\cap C|=3, compute ∣A∪B∪C∣|A\cup B\cup C|.

Hint

Apply the three-set formula.

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Solution

Formula. ∣A∪B∪C∣=20+25+15−10−8−5+3=40|A\cup B\cup C|=20+25+15-10-8-5+3=40.

Conclusion. ∣A∪B∪C∣=40|A\cup B\cup C|=40.