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Exercise 863Calculus › Multivariable calculus › Optimisation in several variablesL1Added 3 Nov 2026

A unique critical point that is a saddle

#saddle#unique critical#Hessian

Statement

Find and classify the critical point of f(x,y)=xy+x3y2f(x,y)=xy+x^3y^2.

Hint

fx=y(1+3x2y)f_x=y(1+3x^2y), fy=x(1+2x2y)f_y=x(1+2x^2y).

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Solution

System. y(1+3x2y)=0y(1+3x^2y)=0 and x(1+2x2y)=0x(1+2x^2y)=0. Only solution: (0,0)(0,0).

Hessian at (0,0)(0,0). fxx=6xy2f_{xx}=6xy^2, fxy=1+6x2yf_{xy}=1+6x^2y, fyy=2x3f_{yy}=2x^3; H(0,0)=(0110)H(0,0)=\begin{pmatrix}0&1\\1&0\end{pmatrix}.

Determinant. det⁡H=−1<0\det H=-1<0: saddle point.

Conclusion. The only critical point (0,0)(0,0) is a saddle.