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Exercise 1597Calculus › Multivariable calculus › Optimisation in several variablesL1Added 3 Nov 2026

Lagrange with exponential objective

#Lagrange#exponential#constrained maximum

Statement

Maximize f(x,y)=exyf(x,y)=e^{xy} subject to x+y=1x+y=1.

Hint

Maximize xyxy under x+y=1x+y=1 via AM-GM.

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Solution

AM-GM. xy≤(x+y2)2=14xy\le\left(\frac{x+y}{2}\right)^2=\frac14, with equality iff x=y=1/2x=y=1/2.

Conclusion. Maximum e1/4e^{1/4} at (1/2,1/2)(1/2,1/2).