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Exercise 1583Number theory › CongruencesL1Added 3 Nov 2026

Fermat's little theorem and pseudoprimes

#Fermat#pseudoprime#compositeness

Statement

Show that 2340≡1(mod341)2^{340}\equiv1\pmod{341}, so 341341 satisfies Fermat's congruence for a=2a=2 despite being composite.

Hint

341=11⋅31341=11\cdot31. Compute 23402^{340} mod 1111 and mod 3131.

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Solution

Mod 1111. 210≡1(mod11)2^{10}\equiv1\pmod{11}, 340=34⋅10340=34\cdot10, so 2340≡1(mod11)2^{340}\equiv1\pmod{11}.

Mod 3131. 25=32≡1(mod31)2^5=32\equiv1\pmod{31}, 340=68⋅5340=68\cdot5, so 2340≡1(mod31)2^{340}\equiv1\pmod{31}.

CRT. By CRT, 2340≡1(mod341)2^{340}\equiv1\pmod{341}.

Conclusion. 341341 is a Fermat pseudoprime to base 22.