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Exercise 819Logic, sets and proofs › Countability and cardinalityL1Added 3 Nov 2026

$\mathbb{Q}$ is dense but countable

#rationals#density#countability

Statement

Explain why Q\mathbb{Q} is countable yet dense in R\mathbb{R}.

Hint

Density means Q\mathbb{Q} meets every nonempty open interval; countability means ∣Q∣=ℵ0|\mathbb{Q}|=\aleph_0.

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Solution

Countability. Shown earlier: ∣Q∣=ℵ0|\mathbb{Q}|=\aleph_0.

Density. For any a<ba<b, some rational p/qp/q lies in (a,b)(a,b) (choose qq large enough).

Contrast. Density and countability coexist; "most" reals are irrational (uncountable), but every interval contains rationals.

Conclusion. Q\mathbb{Q} is a countable dense subset of R\mathbb{R}.